[JAVA] Converting ISO 8601-compliant String to java.util.Date

I am trying to convert an ISO 8601 formatted String to a java.util.Date.

I found the pattern "yyyy-MM-dd'T'HH:mm:ssZ" to be ISO8601-compliant if used with a Locale (compare sample). However, using the java.text.SimpleDateFormat, I cannot convert the correctly formatted String "2010-01-01T12:00:00+01:00". I have to convert it first to "2010-01-01T12:00:00+0100", without the colon. So, the current solution is

SimpleDateFormat ISO8601DATEFORMAT = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ", Locale.GERMANY);
String date = "2010-01-01T12:00:00+01:00".replaceAll("\\+0([0-9]){1}\\:00", "+0$100");
System.out.println(ISO8601DATEFORMAT.parse(date));

which obviously isn't that nice. Am I missing something or is there a better solution?

 

answer

Thanks to JuanZe's comment, I found the Joda-Time magic, it is also described here. So, the solution is

DateTimeFormatter parser2 = ISODateTimeFormat.dateTimeNoMillis();
String jtdate = "2010-01-01T12:00:00+01:00";
System.out.println(parser2.parseDateTime(jtdate));

Or more simply, use the default parser via the constructor:

DateTime dt = new DateTime( "2010-01-01T12:00:00+01:00" ) ;

To me, this is nice.

 

The way that is blessed by Java 7 documentation:

DateFormat df1 = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");
String string1 = "2001-07-04T12:08:56.235-0700";
Date result1 = df1.parse(string1);

DateFormat df2 = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSXXX");
String string2 = "2001-07-04T12:08:56.235-07:00";
Date result2 = df2.parse(string2);

You can find more examples in section Examples at SimpleDateFormat javadoc.

 

[출처] http://stackoverflow.com/questions/2201925/converting-iso-8601-compliant-string-to-java-util-date